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A + B + C = 180^0 . Find the value of cos 2A + cos 2B + cos 2C
Solved z=cos(x2+y2),x=vcos(u),y=vsin(u) find ∂z/∂u and
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College Physic 1 mechanical] So my professor told me to x=(vcos (\alpha ))/(g)[ vsin (\alpha )\sqrt( v^(2)sin^(2)(\alpha ) 2gH)] and I just can't every time I end up with H * vcos
